数据结构趣题——语言翻译

   1: #include <stdio.h>
   2: #include <stdlib.h>
   3: #define STACK_INIT_SIZE 20
   4: #define STACKINCREMENT 10
   5:  
   6: typedef char ElemType;   /*将char类型定义为ElemType*/
   7: typedef struct {       /*定义一个栈类型*/
   8:     ElemType *base;
   9:     ElemType *top;
  10:     int stacksize;
  11: } sqStack;
  12:  
  13:  
  14: void initStack(sqStack *s)
  15: {
  16:     /*内存中开辟一段连续空间作为栈空间,首地址赋值给s->base*/
  17:     s->base = (ElemType *)malloc(STACK_INIT_SIZE * sizeof(ElemType));
  18:  
  19:     if(!s->base) exit(0);     /*分配空间失败*/
  20:  
  21:     s->top = s->base;       /*最开始,栈顶就是栈底*/
  22:     s->stacksize = STACK_INIT_SIZE;   /*最大容量为STACK_INIT_SIZE */
  23: }
  24:  
  25: void Push(sqStack *s, ElemType e) {       /*入栈操作*/
  26:     if(s->top - s->base >= s->stacksize) {
  27:         /*栈满,追加空间*/
  28:         s->base = (ElemType *)realloc(s->base, (s->stacksize +
  29:                                                 STACKINCREMENT) * sizeof(ElemType));
  30:  
  31:         if(!s->base) exit(0);   /*存储分配失败*/
  32:  
  33:         s->top = s->base + s->stacksize;
  34:         s->stacksize = s->stacksize + STACKINCREMENT; /*设置栈的最大容量*/
  35:     }
  36:  
  37:     *(s->top) = e;  /*放入数据*/
  38:     s->top++;
  39: }
  40:  
  41: void Pop(sqStack *s , ElemType *e) {  /*出栈操作*/
  42:     if(s->top == s->base) return;  /*将栈顶元素弹出*/
  43:  
  44:     *e = *--(s->top);              /*修改栈顶指针*/
  45: }
  46:  
  47: int StackLen(sqStack s) {    /*获得栈s的大小*/
  48:     return (s.top - s.base) ;
  49: }
  50:  
  51:  
  52: void  translate(ElemType e, sqStack *s) {
  53:     ElemType c , a;
  54:     sqStack ss1;
  55:  
  56:     if(e >= 97 && e <= 122 )  printf("%c", e);
  57:     else if(e == 'A') printf("%s", "sae");
  58:     else if(e == 'B') printf("%s", "tsaedsae");
  59:     else if(e == '(')
  60:     {
  61:  
  62:         initStack(&ss1); /*初始化栈ss1,用来将括号里面的内容从栈中取出*/
  63:         Pop(&(*s), &c); /*注意*s相当于主函数中的s*/
  64:         a = c; /*保留括号后的第一个元素*/
  65:         Pop(&(*s), &c);
  66:  
  67:         while(c != ')') {
  68:             Push(&ss1, a);
  69:             Push(&ss1, c);
  70:             Pop(&(*s), &c);
  71:         }
  72:  
  73:         Push(&ss1, a);       /*并按语法规定排列后从右至左进入一个新栈ss1*/
  74:  
  75:         while(StackLen(ss1))  /*翻译括号里的内容*/
  76:         {
  77:             Pop(&ss1, &c);      /*取出ss1中的元素c*/
  78:             translate(c, &ss1); /*递归地调用函数 translate对元素c进行翻译*/
  79:         }
  80:     }
  81: }
  82:  
  83: int main()
  84: {
  85:     ElemType e;
  86:     sqStack s1, s2;
  87:     initStack(&s1);   /*初始化栈s1*/
  88:  
  89:     printf("Please input Devil language:\n");
  90:     scanf("%c", &e);
  91:  
  92:     while(e != '#')
  93:     {
  94:         if(e == 'A' || e == 'B' || (e >= 97 && e <= 122) || e == '(' || e == ')')
  95:         {   /*输入的魔王语言合法*/
  96:             Push(&s1, e); /*入栈*/
  97:  
  98:         }
  99:  
 100:         scanf("%c", &e);
 101:     }
 102:  
 103:  
 104:     initStack(&s2);  /*初始化栈s2*/
 105:  
 106:     while(StackLen(s1))
 107:     {
 108:         Pop(&s1, &e);
 109:         //printf("%c\n",e);
 110:         Push(&s2, e); /*将魔王语言从右至左入栈s2*/
 111:     }
 112:  
 113:     printf("The mankind language is:\n");
 114:  
 115:     while(StackLen(s2))
 116:     {
 117:         Pop(&s2, &e);
 118:         translate(e, &s2) ;
 119:     }
 120:  
 121:     return 0;
 122:  
 123: }
原文地址:https://www.cnblogs.com/steven_oyj/p/1746929.html