Financial Management
时间限制：3000 ms | 内存限制：65535 KB
难度：1
描述
Larry graduated this year and finally has a job. He's making a lot of money, but somehow never seems to have enough.
Larry has decided that he needs to grab hold of his financial portfolio and solve his financing problems. The first
step is to figure out what's been going on with his money. Larry has his bank account statements and wants to see how
much money he has. Help Larry by writing a program to take his closing balance from each of the past twelve months and
calculate his average account balance.
输入
The input will be twelve lines. Each line will contain the closing balance of his bank account for a particular month.
Each number will be positive and displayed to the penny. No dollar sign will be included.
输出
The output will be a single number, the average (mean) of the closing balances for the twelve months. It will be rounded
to the nearest penny, preceded immediately by a dollar sign, and followed by the end-of-line. There will be no other spaces
or characters in the output.
样例输入
100.00
489.12
12454.12
1234.10
823.05
109.20
5.27
1542.25
839.18
83.99
1295.01
1.75
样例输出
1581.42来源
[张洁烽]原创
上传者
张洁烽
#include "stdio.h"
int main()
{ int i;
double a[13],sum=0;
for(i=0;i<12;i++)
{scanf("%lf",&a[i]);
sum+=a[i];
}
printf("%.2lf
",sum/12);
return 0;
}
整除个数
时间限制：3000 ms | 内存限制：65535 KB
难度：1
描述
1、2、3… …n这n(0<n<=1000000000)个数中有多少个数可以被正整数b整除。
输入
输入包含多组数据
每组数据占一行，每行给出两个正整数n、b。
输出
输出每组数据相应的结果。
样例输入
2 1
5 3
10 4
样例输出
2
1
2
来源
自编
上传者
mix_math
思路：这充分利用了计算机中除法的运算
/*#include "stdio.h"
int main()
{ int n,b;
int i,j;
while(scanf("%d%d",&n,&b)!=EOF)
{
j=0;
if(b==1)
printf("%d
",n);
else
printf("%d
",n/b);
}
return 0;
}
*/
#include "stdio.h"
int main()
{ int n,b;
int i,j;
while(scanf("%d%d",&n,&b)!=EOF)
{
printf("%d
",n/b);
}
return 0;
}