HDU1012 计算e~

其实主要部分很简单,就是阶乘和累加,关键是输出的格式不好弄,一开始怎么都和标准输出不一致,后来发现输出的格式可以人为控制一下下~~~

贴代码~

 1 #include <stdio.h>
 2 
 3 int jiechen(int x){
 4     int i, sum = 1;
 5     for(i = 1;i <= x;i++){
 6         sum *= i;        
 7     }
 8     return sum;
 9 }
10 
11 int main(){
12     int i,n;
13     double ans=1.0;
14 
15     printf("n e
- -----------
");
16     printf("0 1
");
17     for(n = 1; n < 10; n++){
18         for(i = 1; i <= n; i++){
19             ans += 1/(double)jiechen(i);
20         }
21         if(n == 1){
22             printf("%d %.0f
",n,ans);
23         }
24         else if(n == 2){
25             printf("%d %.1f
",n,ans);
26         }
27         else{
28             printf("%d %.9f
",n,ans);
29         }
30         
31         ans=1.0;
32     }
33     getchar();
34     return 0;
35 }
Everything will be ok in the end. If it is not ok then it is not the end.
原文地址:https://www.cnblogs.com/shirleytian/p/3219181.html