--示例
--示例数据
create table tb(ID int,Time datetime)
insert tb select 1,'2005/01/24 16:20'
union all select 2,'2005/01/23 22:45'
union all select 3,'2005/01/23 0:30'
union all select 4,'2005/01/21 4:28'
union all select 5,'2005/01/20 13:22'
union all select 6,'2005/01/19 20:30'
union all select 7,'2005/01/19 18:23'
union all select 8,'2005/01/18 9:14'
union all select 9,'2005/01/18 18:04'
go
--查询处理：
select case when grouping(b.Time)=1 then 'Total' else b.Time end,
[Mon]=sum(case a.week when 1 then 1 else 0 end),
[Tue]=sum(case a.week when 2 then 1 else 0 end),
[Wed]=sum(case a.week when 3 then 1 else 0 end),
[Thu]=sum(case a.week when 4 then 1 else 0 end),
[Fri]=sum(case a.week when 5 then 1 else 0 end),
[Sat]=sum(case a.week when 6 then 1 else 0 end),
[Sun]=sum(case a.week when 0 then 1 else 0 end),
[Total]=count(a.week)
from(
select Time=convert(char(5),dateadd(hour,-1,Time),108)
--时间交界点是1am,所以减1小时，避免进行跨天处理
,week=(@@datefirst+datepart(weekday,Time)-1)%7
--考虑@@datefirst对datepart的影响
from tb
)a right join(
select id=1,a='16:00',b='19:59',Time='[5pm - 9pm)' union all
select id=2,a='20:00',b='23:59',Time='[9pm - 1am)' union all
select id=3,a='00:00',b='02:59',Time='[1am - 4am)' union all
select id=4,a='03:00',b='07:29',Time='[4am - 8:30am)' union all
select id=5,a='07:30',b='11:59',Time='[8:30am - 1pm)' union all
select id=6,a='12:00',b='15:59',Time='[1pm - 5pm)'
)b on a.Time>=b.a and a.Time<b.b
group by b.id,b.Time with rollup
having grouping(b.Time)=0 or grouping(b.id)=1
go
--删除测试
drop table tb
/*--测试结果
Mon Tue Wed Thu Fri Sat Sun Total
-------------- ----- ----- ----- ----- ----- ------ ---- -------
[5pm - 9pm) 0 1 2 0 0 0 0 3
[9pm - 1am) 0 0 0 0 0 0 2 2
[1am - 4am) 0 0 0 0 0 0 0 0
[4am - 8:30am) 0 0 0 0 1 0 0 1
[8:30am - 1pm) 0 1 0 0 0 0 0 1
[1pm - 5pm) 1 0 0 1 0 0 0 2
Total 1 2 2 1 1 0 2 9
（所影响的行数为 7 行）
--*/
--示例数据
create table tb(ID int,Time datetime)
insert tb select 1,'2005/01/24 16:20'
union all select 2,'2005/01/23 22:45'
union all select 3,'2005/01/23 0:30'
union all select 4,'2005/01/21 4:28'
union all select 5,'2005/01/20 13:22'
union all select 6,'2005/01/19 20:30'
union all select 7,'2005/01/19 18:23'
union all select 8,'2005/01/18 9:14'
union all select 9,'2005/01/18 18:04'
go
--查询处理：
select case when grouping(b.Time)=1 then 'Total' else b.Time end,
[Mon]=sum(case a.week when 1 then 1 else 0 end),
[Tue]=sum(case a.week when 2 then 1 else 0 end),
[Wed]=sum(case a.week when 3 then 1 else 0 end),
[Thu]=sum(case a.week when 4 then 1 else 0 end),
[Fri]=sum(case a.week when 5 then 1 else 0 end),
[Sat]=sum(case a.week when 6 then 1 else 0 end),
[Sun]=sum(case a.week when 0 then 1 else 0 end),
[Total]=count(a.week)
from(
select Time=convert(char(5),dateadd(hour,-1,Time),108)
--时间交界点是1am,所以减1小时，避免进行跨天处理
,week=(@@datefirst+datepart(weekday,Time)-1)%7
--考虑@@datefirst对datepart的影响
from tb
)a right join(
select id=1,a='16:00',b='19:59',Time='[5pm - 9pm)' union all
select id=2,a='20:00',b='23:59',Time='[9pm - 1am)' union all
select id=3,a='00:00',b='02:59',Time='[1am - 4am)' union all
select id=4,a='03:00',b='07:29',Time='[4am - 8:30am)' union all
select id=5,a='07:30',b='11:59',Time='[8:30am - 1pm)' union all
select id=6,a='12:00',b='15:59',Time='[1pm - 5pm)'
)b on a.Time>=b.a and a.Time<b.b
group by b.id,b.Time with rollup
having grouping(b.Time)=0 or grouping(b.id)=1
go
--删除测试
drop table tb
/*--测试结果
Mon Tue Wed Thu Fri Sat Sun Total
-------------- ----- ----- ----- ----- ----- ------ ---- -------
[5pm - 9pm) 0 1 2 0 0 0 0 3
[9pm - 1am) 0 0 0 0 0 0 2 2
[1am - 4am) 0 0 0 0 0 0 0 0
[4am - 8:30am) 0 0 0 0 1 0 0 1
[8:30am - 1pm) 0 1 0 0 0 0 0 1
[1pm - 5pm) 1 0 0 1 0 0 0 2
Total 1 2 2 1 1 0 2 9
（所影响的行数为 7 行）
--*/