verilog循环结构

1. alwaysposedge CLOCK) 
2.       case(i) 
3.    
4.           0: 
5.           if(C1 == 8begin C1 <= 4’d0; i <= i + 1’b1; end 
6.           else begin reg1 <= reg1 + 1’b1; C1 <= C1 + 1’b1; end 
7.    
8.       endcase 
9.                 

10. alwaysposedge CLOCK) 11. case(i) 12. 13. 0,1,2,3,4,5,6,7: 14. begin 15. reg1 <= reg1 + 1’b1; 16. if( C1 == 8 -1 ) begin C1 <= 4’d0; i <= i + 1’b1; end 17. else C1 <= C1 + 1’b1; 18. end 19. 20. endcase

2. for循环

for(i = 0; i < N; i = i + 1)

原文地址:https://www.cnblogs.com/shaogang/p/4936292.html