二叉树java实现

目标

实现二叉树的增加、查找、删除、遍历

实现

 

结点类

public class Node{
int key;
int data;
Node lchild=null;
Node rchild=null;
public Node(int key,int data)
{
	this.key=key;
	this.data=data;
	
}
}


 

 二叉树类:

public class BinaryTree {
	 Node root=null;
	 public void add(int key,int data)
	 {
		 Node node=new Node(key,data);
		 if (root==null)
			 root=node;
		 else 
		 {
			 Node current=root;
			 Node pre=null;
			 while (true)
			 {
				 if (key<current.key)
				 {
					 pre=current;
					 current=current.lchild;
					 if (current==null)
					 {
						 pre.lchild=node;
						 break;
					 }
						 
				 }
				 else 
				 {	 pre=current;
				 current=current.rchild;
				 if (current==null)
					 {
					 pre.rchild=node;
					 break;
					 }
					 
				 }
					 
			 }
			 
		 }
			 
		 
	 }
	 
	 public Node findNode(int key)
	 {
		 Node current=root;
		 while (current!=null)
		 {
			 if (current.key==key)
				 return current;
			 else if (key<current.key)
				 current=current.lchild;
			 else current=current.rchild;
		 }
		 return null;
	 }
	 
	 public int findElement(int key)
	 {
		 Node current=root;
		 while (current!=null)
		 {
			 if (current.key==key)
				 return current.data;
			 else if (key<current.key)
				 current=current.lchild;
			 else current=current.rchild;
		 }
		 return 0;
	 }
	 
	 public boolean delete (int key)
	 {
		 Node current=root;
		 boolean isleftchild=false;
		 Node parent=root;
		 Node currentdouble=null;
		 
		 while (current!=null)
			 
		 {
			 if (root.key==key)
			 {
				 root=null;
				 return true;
			 }
			 
			 if (current.key==key)
			 {
				
				 //当前结点没有孩子,直接删除
				 if (current.lchild==null && current.rchild==null)
				 {
					 if (isleftchild=true)
						 parent.lchild=null;
					 else parent.rchild=null;
					 return true;
					
				 }
				//当前结点没有左孩子,有右孩子
				 if (current.lchild==null && current.rchild!=null)
				 {
					 if (isleftchild=true)
						 parent.lchild=current.rchild;
					 else parent.rchild=current.lchild;
					 return true;
					
				 }
				 
					//当前结点没有右孩子,有左孩子
				 if (current.lchild!=null && current.rchild==null)
				 {
					 if (isleftchild=true)
						 parent.lchild=current.lchild;
					 else parent.rchild=current.lchild;
					
					 return true;
					
					
				 }
				 //右孩子,左孩子都有情况,将左孩子结点替换当前结点,当前结点的右孩子作为替换操作后子树中最右的一个结点
				 if (current.lchild!=null && current.rchild!=null)
				 {
					 if (isleftchild=true)
						 parent.lchild=current.lchild;
					 else parent.rchild=current.lchild;
					
					 currentdouble=current.lchild;
					 Node rparent=null;
					 while (currentdouble!=null)
					 {
						 rparent=currentdouble;
						 currentdouble=currentdouble.rchild;
					 }
					 rparent.rchild=current.rchild;
					return true;
				 }
				 
				 
			 }
			 else if (key<current.key)
			 {   parent=current;
				 current=current.lchild;
				 isleftchild=true;
				 
			 }
			 else {
				 parent=current;
				 current=current.rchild;
				 isleftchild=false;
			 }
				 
			 
		 }
		 
		 return false;
	 }
	 
	 //先序遍历
	 public void preorder(Node node)
	 {
		 if (node!=null)
		 {
			 System.out.println(node.data);
			 preorder(node.lchild);
			 preorder(node.rchild);
			 
		 }
	 }
	 //中序遍历
	 public void midorder(Node node)
	 {
		 if (node!=null)
		 {
			 midorder(node.lchild);
			 
			 System.out.println(node.data);
		
			 midorder(node.rchild);
			 
		 }
	 }
	 
	 //后序遍历
	 public void lastorder(Node node)
	 {
		 if (node!=null)
		 {
			 lastorder(node.lchild);
			 lastorder(node.rchild);
			 System.out.println(node.data);
		
			
			 
		 }
	 }
	 
	 

}


测试类 

public class Test {
	public static void main(String[] args)
	{
		BinaryTree bt=new BinaryTree();
		bt.add(100, 100);
		bt.add(50, 50);
		bt.add(150, 150);
		bt.add(10, 10);
		bt.add(60, 60);
		bt.add(120, 120);
		bt.add(180, 180);
		System.out.println(bt.findElement(50));
		
		System.out.println(bt.root.data);
		bt.preorder(bt.root);
		System.out.println(bt.root.key);
		System.out.println(bt.delete(50));
		bt.preorder(bt.root);
		
		
	}

}


参考资料

http://blog.csdn.net/aaaaaaaa0705/article/details/6713845

http://www.ibm.com/developerworks/cn/java/j-lo-tree/

原文地址:https://www.cnblogs.com/riskyer/p/3395164.html