【每日一题】1734. 解码异或后的排列

https://leetcode-cn.com/problems/decode-xored-permutation/

class Solution {
    public int[] decode(int[] encoded) {
        int n = encoded.length + 1;
        int total = 0;
        for (int i = 1; i <= n; i++) {
            total ^= i;
        }
        int odd = 0;
        for (int i = 1; i < n - 1; i += 2) {
            odd ^= encoded[i];
        }
        int[] perm = new int[n];
        perm[0] = total ^ odd;
        for (int i = 0; i < n - 1; i++) {
            perm[i + 1] = perm[i] ^ encoded[i];
        }
        return perm;
    }
}
原文地址:https://www.cnblogs.com/realzhaijiayu/p/14759374.html