LeetCode OJ——Two Sum

http://oj.leetcode.com/problems/two-sum/

求是否存在两个数的和为target,暴力法,两层循环

#include <iostream>
#include <algorithm>
#include <vector>
using namespace std;


class Solution {

public:
    vector<int> twoSum(vector<int> &numbers, int target) {
        // Note: The Solution object is instantiated only once and is reused by each test case.
        //sort(numbers.begin(),numbers.end());

        vector<int> answer;
        answer.clear();
        if(numbers.size()<2)
            return answer;
        for(int index = 0;index<numbers.size()-1;index++)
        {
            for(int index2 = index+1;index2<numbers.size();index2++)
            {
                if(numbers[index2] == target - numbers[index])
                {
                    answer.push_back(index+1);
                    answer.push_back(index2+1);
                    return answer;
                }
            }
        }
        return answer;
    }
};


int main()
{
    Solution * mysolution = new Solution();
    vector<int> numbers;
    numbers.push_back(150);
    numbers.push_back(24);
    numbers.push_back(79);
    numbers.push_back(50); 
        numbers.push_back(88);
    numbers.push_back(345);
    numbers.push_back(3); 
    vector<int> ans;
    int i = 0;
        ans= mysolution->twoSum(numbers,200 );
     while(i!=ans.size())
    {
          cout<<ans[i]<<" ";
          i++;
    } 
    return 0;
}
原文地址:https://www.cnblogs.com/qingcheng/p/3389134.html