leetcode_question_64 Minimum Path Sum

Given a m x n grid filled with non-negative numbers, find a path from top left to bottom right which minimizes the sum of all numbers along its path.

Note: You can only move either down or right at any point in time.

 

int minPathSum(vector<vector<int> > &grid) {
        // Start typing your C/C++ solution below
        // DO NOT write int main() function
        int row = grid.size();
    	int col = grid[0].size();

		int**dp = new int*[row];
		for(int i=0; i< row; i++)
			dp[i] = new int[col];

		dp[0][0] = grid[0][0];
		for(int j =1; j < col; j++)
			dp[0][j] = dp[0][j-1] + grid[0][j];
		
		for(int i = 1; i < row; i++)
			for(int j =0; j < col; j++)
				if(j == 0)dp[i][0] = dp[i-1][0] + grid[i][0];
				else{
					int tmp = dp[i-1][j] < dp[i][j-1] ? dp[i-1][j] : dp[i][j-1];
					dp[i][j] = tmp + grid[i][j];
				}

		int tmp = dp[row-1][col-1];
    	for(int i = 0; i < row; i++)
			delete[] dp[i];
		delete[] dp;
		return tmp;
    }


原文地址:https://www.cnblogs.com/pangblog/p/3322898.html