MySQL中查询获取每个班级成绩前三名的学生信息


CREATE TABLE t_testscore(    pk_id INT PRIMARY KEY,    c_name VARCHAR(50) ,    c_score INT,    c_class INT )DEFAULT CHARSET=utf8;

INSERT INTO t_testscore VALUES (1, '张三6', 66, 1),(2, '张三5', 65, 1),(3, '张三4', 64, 1), (4, '张三3', 63, 1),(5, '张三2', 62, 1);

INSERT INTO t_testscore VALUES (11, '李四6', 76, 2),(12, '李四5', 75, 2),(13, '李四4', 74, 2), (14, '李四3', 73, 2),(15, '李四2', 72, 2);

SELECT * FROM t_testscore t  

  WHERE EXISTS(SELECT COUNT(*) FROM t_testscore ts  WHERE ts.c_score>=t.c_score  GROUP BY ts.c_class  HAVING COUNT(*)<=3)  

    ORDER BY c_class,c_score DESC;
当使用group by 查询时报错:  this is incompatible with sql_mode=only_full_group_by, 原因是:  在使用group by 时, select 后跟的查询对象不是聚合函数,并且查询对象(可能有多个)
没有在group by 中出现,则会报 this is incompatible with sql_mode=only_full_group_by 错误. 
例如在上表中使用查询语句select c_name from t_testscore group by  c_class就会报错, 因为c_name 没有在group by 中出现。
但是使用查询语句 select count(*)  from t_testscore group by c_class 就不会报错, 因为count() 是聚合函数.

原文地址:https://www.cnblogs.com/nyist-xsk/p/10636985.html