Leetcode 200 岛屿数量 压缩路径并查集与DFS

  JAVA DFS 解法:

public final int numIslands(char[][] grid) {
        int re = 0;
        for (int x = 0; x < grid.length; x++) {
            for (int y = 0; y < grid[0].length; y++) {
                if (grid[x][y] == '1') {
                    search(grid, x, y);
                    re++;
                }
            }
        }
        return re;
    }

    private final void search(char[][] grid, int x, int y) {
        if (!isInBoard(grid, x, y) || grid[x][y] == '0') {
            return;
        }
        grid[x][y] = '0';
        search(grid, x-1, y);
        search(grid, x, y + 1);
        search(grid, x + 1, y);
        search(grid, x, y - 1);
    }

    private final boolean isInBoard(char[][] grid, int x, int y) {
        if (x < 0 || x >= grid.length || y < 0 || y >= grid[0].length) {
            return false;
        }
        return true;
    }

  JS DFS 解法:

/**
 * @param {character[][]} grid
 * @return {number}
 */
var numIslands = function (grid) {
    let re = 0;
    for (let x = 0; x < grid.length; x++) {
        for (let y = 0; y < grid[0].length; y++) {
            if (grid[x][y] == 1) {
                search(grid, x, y);
                re++;
            }
        }
    }
    return re;
};

var search = function (grid, x, y) {
    if (!isInBoard(grid, x, y) || grid[x][y] == '0') {
        return;
    }
    grid[x][y] = '0';
    search(grid, x - 1, y);
    search(grid, x + 1, y);
    search(grid, x, y - 1);
    search(grid, x, y + 1);
}

var isInBoard = function (grid, x, y) {
    if (x < 0 || y < 0 || x >= grid.length || y >= grid[0].length) {
        return false;
    }
    return true;
}

   JAVA 并查集:

    class UnionFind {
        int rootNum;
        int[] parent;

        UnionFind(char[][] grid) {
            this.parent = new int[grid.length * grid[0].length];
            this.rootNum = 0;
            initParent(grid);
        }

        private final void initParent(char[][] grid) {
            int len = grid[0].length;
            for (int i = 0; i < parent.length; i++) {
                int x = i / len;
                int y = i % len;
                if (grid[x][y] == '1') {
                    parent[i] = i;
                    this.rootNum++;
                } else {
                    parent[i] = -1;
                }
            }
        }

        private final int find(int num) {
            if (parent[num] == num) {
                return num;
            }
            return find(parent[num]);
        }

        private final void uion(int node1, int node2) {
            int root1 = find(node1);
            int root2 = find(node2);
            if (root1 == root2) {
                return;
            }
            parent[root2] = root1;
            rootNum--;
        }
    }

    public final int numIslands(char[][] grid) {
        if (grid.length == 0 || grid[0].length == 0) {
            return 0;
        }
        UnionFind unionFind = new UnionFind(grid);
        for (int i = 0; i < grid.length; i++) {
            for (int j = 0; j < grid[0].length; j++) {
                if (grid[i][j] == '1') {
                    grid[i][j] = '0';
                    int point = i * grid[0].length + j;
                    if (i > 0 && grid[i - 1][j] == '1') {
                        unionFind.uion(point, point - grid[0].length);
                    }
                    if (i < grid.length - 1 && grid[i + 1][j] == '1') {
                        unionFind.uion(point, point + grid[0].length);
                    }
                    if (j > 0 && grid[i][j - 1] == '1') {
                        unionFind.uion(point, point - 1);
                    }
                    if (j < grid[0].length - 1 && grid[i][j + 1] == '1') {
                        unionFind.uion(point, point + 1);
                    }
                }
            }
        }
        return unionFind.rootNum;
    }

  JS 并查集:

var numIslands = function (grid) {
    if (grid.length == 0 || grid[0].length == 0) {
        return 0;
    }
    let unionFound = new UnionFound(grid);
    for (let i = 0; i < grid.length; i++) {
        for (let j = 0; j < grid[0].length; j++) {
            if (grid[i][j] == 1) {
                let point = i * grid[0].length + j;
                if (i > 0 && grid[i - 1][j] == 1) {
                    unionFound.union(point, point - grid[0].length);
                }
                if (i < grid.length - 1 && grid[i + 1][j] == 1) {
                    unionFound.union(point, point + grid[0].length);
                }
                if (j > 0 && grid[i][j - 1] == 1) {
                    unionFound.union(point, point - 1);
                }
                if (j < grid[0].length && grid[i][j + 1] == 1) {
                    unionFound.union(point, point + 1);
                }
            }
        }
    }
    return unionFound.rootNum;
}

var UnionFound = function (grid) {
    this.parent = new Array(grid.length * grid[0].length).fill(-1);
    this.rootNum = 0;
    for (let i = 0; i < grid.length; i++) {
        for (let j = 0; j < grid[0].length; j++) {
            if (grid[i][j] == 1) {
                let point = i * grid[0].length + j;
                this.parent[point] = point;
                this.rootNum++;
            }
        }
    }

    this.find = function (num) {
        if (this.parent[num] == num) {
            return num;
        }
        return this.find(this.parent[num]);
    }

    this.union = function (num1, num2) {
        let root1 = this.find(num1);
        let root2 = this.find(num2);
        if (root1 == root2) {
            return;
        }
        this.parent[root2] = root1;
        this.rootNum--;
    }
}
当你看清人们的真相,于是你知道了,你可以忍受孤独
原文地址:https://www.cnblogs.com/niuyourou/p/13539248.html