二叉树路径和


#include "stdafx.h"
#include <vector>
#include <iostream>
using namespace std;

#define A 16

//二叉树前序遍历序列
int buffer[16]={1,2,4,-1,-1,5,-1,-1,3,6,-1,-1,7,-1,-1,-100};

//二叉树结构体
typedef struct binary_tree_node
{
	int data;
	struct binary_tree_node* ltree;
	struct binary_tree_node* rtree;
}Btnode;

//创建新节点
Btnode* create_node(void)
{
	Btnode* node;
	node=(Btnode*)malloc(sizeof(Btnode));
	return node;
}

//据前序序列创建二叉树
/*
	明白问题:

	(1)何时进行二叉树分支的切换

		①左分支遍历到叶子节点时

		②右分支有新的节点增加时

	(2)何时节点入栈

		新增加的非空节点

	(3)何时节点出栈

		某分支遍历到叶子节点时
*/
Btnode* create_tree(int* buf)
{
	Btnode* root;
	Btnode* pnode,*temp;
	Btnode* s[A];
	bool ltree=true;
	int index=0;
	int m=0;
	
	root=create_node();
	root->data=buf[index++];
	s[m++]=root;
	pnode=root;

	while(buf[index]!=-100)
	{
		if(ltree==true)
		{
			if(buf[index]==-1)
			{
				pnode->ltree=NULL;
				index++;
				ltree=false;
				pnode=s[--m];
			}
			else
			{
				temp=create_node();
				temp->data=buf[index++];
				pnode->ltree=temp;
				s[m++]=temp;
				pnode=temp;
			}
		}
		else
		{
			if(buf[index]==-1)
			{
				pnode->rtree=NULL;
				index++;
				pnode=s[--m];
			}
			else
			{
				temp=create_node();
				temp->data=buf[index++];
				pnode->rtree=temp;
				s[m++]=temp;
				pnode=temp;
				ltree=true;
			}
		}
	}

	return root;
}

//递归方法前序遍历
void preorder_traversal(Btnode* pnode)
{
	if(pnode!=NULL)
	{
		printf("%d ",pnode->data);
	}
	else
	{
		return;
	}

	preorder_traversal(pnode->ltree);
	preorder_traversal(pnode->rtree);
	return;
}


vector<Btnode*> s;
int sum=0;
int SPEC=100;

void printPath(void)
{
	vector<Btnode*>::iterator it=s.begin();

	cout<<" Path: ";
	while(it!=s.end())
	{
		cout<<(*it)->data<<" ";
		++it;
	}
	cout<<endl;
}

void postSum(Btnode* node)
{
	if(node->ltree==NULL && node->rtree==NULL)
	{
		sum+=node->data;
		s.push_back(node);
		//if(sum==SPEC)
		{
			cout<<sum<<" ";
			printPath();
		}
		if(!s.empty())
		{
			sum-=s.back()->data;
			s.pop_back();
		}
		return;
	}
	else
	{
		sum+=node->data;
		s.push_back(node);
		postSum(node->ltree);
		postSum(node->rtree);
	}
	if(!s.empty())
	{
		sum-=s.back()->data;
		s.pop_back();
	}
	return;
}


int main(void)
{
	Btnode* root;
	root=create_tree(buffer);
	
	postSum(root);
	
	system("pause");
	return 0;
}

原文地址:https://www.cnblogs.com/mfrbuaa/p/4246319.html