py程序----两个判断回文的程序

1

 a = input("输入一段话")
 b = int(len(a))   #算出这段话的字数
 c = int(len(a)/2)
 print(b)
 if b == 2 and a[0] == a[-1]:
     print("是回文")
     quit()
 elif b == 3 and a[0] == a[-1]:
     print("是回文")
     quit()
 elif b == c*2 and a[c] == a[c - 1]:
     print("是回文")
 elif b == c*2+1 and a[c] == a[-c -1]:
     print("是回文")

2

s = input('输入一段话：') 
if not s: 
	print('不要输入空字符串！') 
	s = input('请重新输入一个字符串：') 
	
a = len(s) 
i = 0 
count = 1 
while i <= (a/2): 
	if s[i] == s[a-i-1]: 
	count = 1 i += 1 
	else: 
	count = 0 
	break 
	
if count == 1: 
	print('是回文') 
else: 
	print('不是回文')

最后附赠一个装13大法

sen = input('请输入需要判断的语句：')
print('是回文') if sen.strip()==sen.strip()[::-1] else print('不是回文')