Python实现求1-1000以内的素数

def func():
    for i in range(2,1000):
        # count表示被整除的次数
        count = 0
        for j in range(1,i+1):
            if i%j==0:
                count+=1
            # count==2说明,该数字只能被1和它本身整除
            if count==2:
                if i==j:
                    print(i)


func()
原文地址:https://www.cnblogs.com/lxmtx/p/11840130.html