POJ1013Counterfeit Dollar

这个题主要是判断硬币真假,可能轻可能重,称三次,要输出哪枚是假币,还要输出是重的还是轻的,所以最主要的是标记变量

 1 #include<cstdio>
 2 #include<cstring>
 3 #include<cmath>
 4 #include<iostream>
 5 using namespace std ;
 6 
 7 int main()
 8 {
 9     int n ;
10     while(cin>>n )
11     {
12         int a['L'+3] ;
13         for(int k = 1 ; k <= n ; k++)
14         {
15             memset(a,0,sizeof(a)) ;  //没被标记
16             char ch[50],sh[50] ,ju[50];
17             for(int j = 1 ; j <= 3 ; j++)
18             {
19                 cin>>ch>>sh>>ju;
20                 if(strcmp(ju,"even")==0)
21                 {
22                     for(int i = 0 ; i <  strlen(ch) ; i++)
23                     {
24                         a[ch[i]] = 1000 ;//绝对真币为-1
25                         a[sh[i]] = 1000 ;
26                     }
27                 }
28                 else if(strcmp(ju,"up") == 0)
29                 {
30                     for(int i = 0 ; i < strlen(ch) ; i++)
31                     {
32                         if(a[ch[i]] != 1000)
33                             a[ch[i]]++;//
34                         if(a[sh[i]] != 1000)
35                             a[sh[i]]-- ;
36                     }
37                 }
38                 else if(strcmp(ju,"down") == 0)
39                 {
40                     for(int i = 0 ; i < strlen(ch) ; i++)
41                     {
42                         if(a[ch[i]] != 1000)
43                             a[ch[i]] --;
44                         if(a[sh[i]] != 1000)
45                             a[sh[i]]++ ;
46                     }
47                 }
48             }
49             int max = 0 ;
50             char count ;
51             for(int j = 'A' ; j <= 'L' ; j++)
52             {
53                 if(a[j] == 1000)
54                     continue ;
55                 if( fabs(a[j]) >= max)
56                 {
57                     max = fabs(a[j]) ;
58                     count = j ;
59                 }
60             }
61             cout<<count<< " is the counterfeit coin and it is ";
62             if(a[count] > 0)
63                 cout<<"heavy."<<endl ;
64             else
65                 cout<< "light."<<endl ;
66         }
67     }
68     return 0 ;
69 }
View Code
原文地址:https://www.cnblogs.com/luyingfeng/p/3231284.html