Algs4-2.2.23-2比较正文中实现的归并和反向复制辅助数组归并之间的性能

2.2.23改进。用实验评估正文中所提到的归并排序的三项改进(请见练习2.2.11)的效果,并比较正文中实现的归并和练习2.2.10所实现的归并之间的性能。根据经验给出应该在何时为子数组切换到插入排序。
2)比较正文中实现的归并和反向复制辅助数组归并之间的性能(练习2.2.10)
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public class E2d2d23d2
{
    public static double time (String alg,Double[] a)
    {
        Stopwatch timer =new Stopwatch();
        if(alg.equals("Merge")) Merge.sort(a);
        if(alg.equals("Merge2")) E2d2d10.sort(a);
        return timer.elapsedTime();
    }
   
    public static double timeRandomInput(String alg,int N,int T)
    {
        double total =0.0;
        Double[] a=new Double[N];
        for (int t=0;t<T;t++)
        {
            for (int i=0;i<N;i++)
                a[i]=StdRandom.uniform();
            total+=time(alg,a);
        }
        return total/T;
    }//end timeRandomInput

   
    public static void main(String[] args)
    {
        int N=Integer.parseInt(args[0]);
        int T=Integer.parseInt(args[1]);
       
        StdOut.printf("For %d random Doubles %d times sort ",N,T);

        double t1=timeRandomInput("Merge",N,T);
        double t2=timeRandomInput("Merge2",N,T);
        StdOut.printf("Merge spend time=%.2f  Merge2 spendtime=%.2f Merge2/Merge rate=%.2f ",t1,t2,t2/t1);
    }
}


public class E2d2d10
{
    private static Comparable[] aux;
    public static void sort(Comparable[] a)
    {
        aux=new Comparable[a.length];
        sort(a,0,a.length-1);
    }
    public static void sort(Comparable[] a,int lo,int hi)
    {
        if (hi<=lo) return;
        int mid=lo+(hi-lo)/2;
        sort(a,lo,mid);
        sort(a,mid+1,hi);
        merge(a,lo,mid,hi);
    }
  
    public static void merge(Comparable[] a,int lo,int mid,int hi)
    {
   
        int i=lo,j=hi;
        for (int k=lo;k<=mid;k++)
           aux[k]=a[k];
        /*
       //k 索引更容易理解的方式
        for (int k=0;mid+1+k<=hi;k++)
               aux[mid+1+k]=a[hi-k];
        */
        for (int k=mid+1;k<=hi;k++)
               aux[k]=a[hi-k+mid+1];
 
      
        for(int k=lo;k<=hi;k++)
           if (less(aux[j],aux[i])) a[k]=aux[j--];
           else                           a[k]=aux[i++];
      }
    private static boolean less(Comparable v,Comparable w)
    { return v.compareTo(w)<0;}
  
    public static boolean isSorted(Comparable[] a)
    {
      for(int i=1;i<a.length;i++)
        if(less(i,i-1)) return false;
      return true;
    }

}



import java.util.Arrays;
public class Merge
{
    private static Comparable[] aux;
    public static void sort(Comparable[] a)
    {
        aux=new Comparable[a.length];
        sort(a,0,a.length-1);
    }
    public static void sort(Comparable[] a,int lo,int hi)
    {
        if (hi<=lo) return;
        int mid=lo+(hi-lo)/2;
        sort(a,lo,mid);
        sort(a,mid+1,hi);
        merge(a,lo,mid,hi);
    }
   
    public static void merge(Comparable[] a,int lo,int mid,int hi)
    {
        int i=lo,j=mid+1;
        for (int k=lo;k<=hi;k++)
        aux[k]=a[k];
       
        for(int k=lo;k<=hi;k++)
        if        (i>mid) a[k]=aux[j++];
        else if (j>hi)    a[k]=aux[i++];
        else if (less(aux[j],aux[i])) a[k]=aux[j++];
        else            a[k]=aux[i++];
      }
    private static boolean less(Comparable v,Comparable w)
    { return v.compareTo(w)<0;}

     public static boolean isSorted(Comparable[] a)
    {
      for(int i=1;i<a.length;i++)
        if(less(a[i],a[i-1])) return false;
      return true;
    }

}

原文地址:https://www.cnblogs.com/longjin2018/p/9860123.html