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操作 |
函数 |
使用方法 |
备注 |
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索引 |
index |
in: example.index(‘creative’) --- 1 in:example[1,] --- [’creative’, [’京东’，996]] |
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赋值 |
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in: example[1] = [‘commonplace’] --- [1, ‘commonplace’, [’京东’，996]] in: example[2,] = [[‘国企’,855],[‘阿里’，996],[‘博士生’,007]] |
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删除 |
clear pop 索引赋空值 |
in: example.clear --- [] in: example.pop() --- [’京东’，996]( example== [1, ’creative’]) in: example[1] = [] --- [1, [’京东’，996]] |
clear：就地清空列表的内容 pop : 从列表中删除一个元素，并返回这一元素 |
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插入 |
insert 索引赋值 |
in: example.insert(1,’ commonplace’) --- [1, ’ commonplace’,’creative’, [’京东’，996]] in: example[1:1]=[ ’ anyway’] --- [1, ’ anyway’ ,’creative’, [’京东’，996]] |
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扩展与拼接 |
extend append |
a = [1,2,3];b= [4,5,6] in: a.extend(b) ---- [1,2,3,4,5,6] in: a.append(7) --- [1,2,3,7] in: a+b [1,2,3,4,5,6](但是，a未改变) |
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复制 |
copy |
ex = example ex[3] = [‘奋斗==全勤投入？’] in： example --- [1, ’creative’, [’京东’，996]，‘奋斗==全勤投入？] in: ex= example.copy() ex[3] = [‘奋斗==全勤投入？’] in： example --- [1, ’creative’, [’京东’，996]] |
“=”，传递位置（指针） copy:只复制元素
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计数 |
count |
in: [‘stay’,’hungrey’,’stay’,’foolish’].count(‘stay’) --- 2 |
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排序 |
sort sorted |
x=[4,6,2,1,7,9] x.sort() in: x --- [1,2,4,7,9] in: y=sorted(x), x --- [1,2,4,7,9], [4,6,2,1,7,9] |
sort用于对列表就地排序； sorted不改变原来类别的元素的顺序 |