oracle_存储过程_有参数_获取部门装置层级树

create or replace procedure P_UTIL_TREE(P_APPL_NAME in VARCHAR2,
P_HIERARCHY_TYP in VARCHAR2,
TREETYPE in varchar2,
USERCODE in VARCHAR2,
P_CUR OUT SYS_REFCURSOR) is
begin
OPEN P_CUR FOR
with v_util_tree as
(select DISTINCT H.PARENT_EQ_NAME,
H.EQ_NAME,
E.DSCR,
H.SEQ,
W.EDITABLE,
E.TYP
from ip_equip_hierarchy h,
ip_eq E,
(SELECT U.ROLE_ID, T.HIERARCHY_TYP, T.EQ_NAME, T.EDITABLE
FROM A_PT_ROLES_PURVIEW T, A_PT_ROLES_USERS U
WHERE T.HIERARCHY_TYP = P_HIERARCHY_TYP
AND T.ROLE_ID = U.ROLE_ID
AND upper(U.USER_ID) = upper(USERCODE)) w
WHERE H.HIERARCHY_TYP = P_HIERARCHY_TYP
AND H.EQ_NAME = E.EQ_NAME
and e.typ <> 'TANK'
and e.typ <> 'LGTANK'
and e.typ <> 'POST'
AND H.HIERARCHY_TYP = W.HIERARCHY_TYP(+)
AND H.EQ_NAME = W.EQ_NAME(+)
start with H.EQ_NAME in (SELECT T.EQ_NAME
FROM A_PT_ROLES_PURVIEW T, A_PT_ROLES_USERS U
WHERE T.HIERARCHY_TYP = P_HIERARCHY_TYP
AND T.ROLE_ID = U.ROLE_ID
AND upper(U.USER_ID) = upper(USERCODE))
CONNECT BY PRIOR H.PARENT_EQ_NAME = H.EQ_NAME
AND H.HIERARCHY_TYP = P_HIERARCHY_TYP
UNION ALL
SELECT '0',EQ_NAME, DSCR, 0 AS SEQ, '', TYP
FROM V_IP_EQ
WHERE EQ_NAME = '$ASSET'
ORDER BY SEQ )

SELECT DSCR as TEXT, EQ_NAME as ID, PARENT_EQ_NAME, TYP
FROM v_util_tree A;
end P_UTIL_TREE;

原文地址:https://www.cnblogs.com/liuqiyun/p/6796228.html