628. Maximum Product of Three Numbers

Given an integer array, find three numbers whose product is maximum and output the maximum product.

Example 1:

Input: [1,2,3]
Output: 6

Example 2:

Input: [1,2,3,4]
Output: 24

Note:

  1. The length of the given array will be in range [3,104] and all elements are in the range [-1000, 1000].
  2. Multiplication of any three numbers in the input won't exceed the range of 32-bit signed integer.

解题思路:

  排序后两种情况,3个都是正数最大,2个是负数最小,一个是正数最大比大小。

  

  1. class Solution {  
  2. public:  
  3.     int maximumProduct(vector<int>& nums) {  
  4.           
  5.         if(nums.size()<3) return 0;  
  6.         if(nums.size()==3) return nums[0]*nums[1]*nums[2];  
  7.         int max_product=1;  
  8.         int max_neg=1;  
  9.         int n =nums.size();  
  10.         sort(nums.begin(),nums.end());  
  11.           
  12.         if(nums[n-3]>=0)  
  13.         max_product = nums[n-3]*nums[n-2]*nums[n-1];  
  14.           
  15.         if(nums[1]<=0)  
  16.             max_neg=nums[0]*nums[1]*nums[n-1];  
  17.           
  18.         return max_product>=max_neg?max_product:max_neg;  
  19.           
  20.           
  21.     }  
  22. };  
原文地址:https://www.cnblogs.com/liangyc/p/8847647.html