LeetCode:Remove Element

Given an array and a value, remove all instances of that value in place and return the new length.

The order of elements can be changed. It doesn't matter what you leave beyond the new length.

 1 class Solution{
 2 public:
 3     int removeElement(int A[],int n, int elem){
 4         int i=0,j=0;
 5         if(n<=0)
 6         {
 7             return n;
 8         }
 9         while(i<n)
10         {
11             if(A[i]!=elem)
12             {
13                 A[j++]=A[i];
14             }
15             i++;
16         }
17         return j;
18     }
19 };
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原文地址：https://www.cnblogs.com/levicode/p/3855135.html