关于链表

/*
public class RandomListNode {
    int label;
    RandomListNode next = null;
    RandomListNode random = null;

    RandomListNode(int label) {
        this.label = label;
    }
}
*/
import java.util.*;
public class Solution {
    public RandomListNode Clone(RandomListNode pHead)
    {
        if(pHead==null)
            return null;
        
        RandomListNode Lphead=pHead;
        Map<RandomListNode,RandomListNode> map=new HashMap<>();
        while(Lphead!=null){
            map.put(Lphead,new RandomListNode(Lphead.label) ) ;
            Lphead=Lphead.next;
        }
        Lphead=pHead;
        while(Lphead!=null){
            map.get(Lphead).next=map.get(Lphead.next);
            Lphead=Lphead.next;
        }
        Lphead=pHead;
        while(Lphead!=null){
            map.get(Lphead).random=map.get(Lphead.random);
            Lphead=Lphead.next;
        }
        
        return map.get(pHead);
    }
}

/*
public class ListNode {
    int val;
    ListNode next = null;

    ListNode(int val) {
        this.val = val;
    }
}*/
public class Solution {
    public ListNode Merge(ListNode p1,ListNode p2) {
        if(p1==null)
            return p2;
        if(p2==null)
            return p1;
        
        ListNode head=new ListNode(-1);
        ListNode L=head;
        while(p1!=null && p2!=null){
            if(p1.val<p2.val){
                L.next=p1;
                p1=p1.next;
                L=L.next;
            }else{
                L.next=p2;
                p2=p2.next;
                L=L.next;
            }
        }
        
        while(p1!=null){
                L.next=p1;
                p1=p1.next;
                L=L.next;
        }
        while(p2!=null){
                L.next=p2;
                p2=p2.next;
                L=L.next;
        }
        return head.next;
        
    }
}

/**
 * Definition for singly-linked list.
 * public class ListNode {
 *     int val;
 *     ListNode next;
 *     ListNode(int x) { val = x; }
 * }
 */
class Solution {
    public ListNode removeNthFromEnd(ListNode head, int n) {

        ListNode fast=head;
        ListNode slow=head;
        for(int i=0;i<n;i++)  //首先让快指针走n步
            fast=fast.next;
        if(fast==null){   //此时说明链表j正好有n个元素,因此需要删除第一个
            head=head.next;
        }else{
            while(fast.next!=null){
                fast=fast.next;
                slow=slow.next;   //满指针到达要删除结点的前一个结点
            }
            slow.next=slow.next.next; //删除结点
        }
        return head;
    }
}
原文地址:https://www.cnblogs.com/lemonzhang/p/13092291.html