1044: 数圈

1044: 数圈

时间限制: 1 Sec  内存限制: 128 MB
提交: 231  解决: 97
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题目描述

以1为中心，用2,3,4, ..., n, ..., n*n的数字围绕着中心输出数圈， 如若n=4，则

7 8 9 10

6 1 2 11

5 4 3 12

16 15 14 13

输入

一个整数n(1<=n<=10)

输出

数圈矩阵

样例输入

5

样例输出

21 22 23 24 25
20 7 8 9 10
19 6 1 2 11
18 5 4 3 12
17 16 15 14 13

提示

 

来源

 #include <iostream>
using namespace std;
int main(){
 int i,j,n;
 int a[10][10]={{73,74,75,76,77,78,79,80,81,82},
 {72,43,44,45,46,47,48,49,50,83},
 {71,42,21,22,23,24,25,26,51,84},
 {70,41,20,7,8,9,10,27,52,85},
 {69,40,19,6,1,2,11,28,53,86},
 {68,39,18,5,4,3,12,29,54,87},
 {67,38,17,16,15,14,13,30,55,88},
 {66,37,36,35,34,33,32,31,56,89},
 {65,64,63,62,61,60,59,58,57,90},
 {100,99,98,97,96,95,94,93,92,91}};
 while(cin>>n){
   if(n==1) cout<<1<<endl;
   else if(n==2){
    cout<<1<<" "<<2<<endl;
    cout<<4<<" "<<3<<endl;
   }
      else if(n%2!=0){
       for(i=4-n/2;i<=4+n/2;i++){
         for(j=4-n/2;j<=4+n/2;j++){
          if(j==4+n/2) cout<<a[i][j];
          else
          cout<<a[i][j]<<" ";
         }
         cout<<endl;
       }
      }else{
       for(i=4-(n/2-1);i<=4+n/2;i++){
         for(j=4-(n/2-1);j<=4+n/2;j++){
          if(j==4+n/2) cout<<a[i][j];
          else
          cout<<a[i][j]<<" ";
         }
         cout<<endl;
       }
      }
 }
 return 0;
}