LeetCode Valid Anagram

Given two strings s and t, write a function to determine if t is an anagram of s.
For example,
s = "anagram", t = "nagaram", return true.
s = "rat", t = "car", return false.
Note:
You may assume the string contains only lowercase alphabets.

感觉已经到了懒癌晚期了:

class Solution {
public:
    bool isAnagram(string s, string t) {
        int slen = s.size();
        int tlen = t.size();
        if (slen != tlen) {
            return false;
        }
        sort(s.begin(), s.end());
        sort(t.begin(), t.end());
        int i = 0;
        while (i < slen && s[i] == t[i]) i++;
        return i == slen;
    }
};

改进一下:

class Solution {
public:
    bool isAnagram(string s, string t) {
        int slen = s.size();
        int tlen = t.size();
        if (slen != tlen) {
            return false;
        }
        int count[128] = {0};
        for (int i=0; i<slen; i++) {
            count[s[i]]++;
        }
        for (int i=0; i<tlen; i++) {
            if (--count[t[i]] < 0) {
                return false;
            }
        }
        return true;
    }
};
原文地址:https://www.cnblogs.com/lailailai/p/4700406.html