[HIHO1152]Lucky Substrings（暴力，枚举）

题目链接：http://hihocoder.com/problemset/problem/1152

题意：给一个字符串，找所有的满足不同字符数为斐波那契数的子串。

暴力，枚举。

 1 #include <bits/stdc++.h>
 2 using namespace std;
 3 
 4 const int maxn = 111;
 5 const int maxm = 66;
 6 int n;
 7 int fib[maxm];
 8 char s[maxn];
 9 set<string> ret;
10 set<int> vis;
11 
12 bool ok(int l, int r) {
13     set<char> t;
14     for(int i = l; i <= r; i++) t.insert(s[i]);
15     if(vis.find(t.size()) != vis.end()) return 1;
16     return 0;
17 }
18 
19 int main() {
20     // freopen("in", "r", stdin);
21     char buf[maxn];
22     memset(fib, 0, sizeof(fib));
23     vis.clear();
24     fib[0] = fib[1] = fib[2] = 1;
25     fib[3] = 2;
26     vis.insert(1);
27     vis.insert(2);
28     for(int i = 4; i < maxm; i++) {
29         fib[i] = fib[i-1] + fib[i-2];
30         vis.insert(fib[i]);
31     }
32     while(~scanf("%s", s)) {
33         n = strlen(s);
34         ret.clear();
35         for(int l = 0; l < n; l++) {
36             for(int r = l; r < n; r++) {
37                 if(ok(l, r)) {
38                     memset(buf, 0, sizeof(buf));
39                     for(int i = l; i <= r; i++) buf[i-l] = s[i];
40                     ret.insert(buf);
41                 }
42             }
43         }
44         for(set<string>::iterator it = ret.begin(); it != ret.end(); it++) {
45             cout << *it << endl;
46         }
47     }
48     return 0;
49 }