[URAL1057]Amount of Degrees(数位dp)

题目链接:http://acm.timus.ru/problem.aspx?space=1&num=1057

题意:求[L,R]区间内的数转换成b进制后可以变成k个b进制的幂和。

其实就是求区间内的数里有几个数,使得这些数转换成b进制有k个1存在。

转换成对应进制,然后dfs。每一位插0或者1就行了。(这题其实前导零不用处理)

 1 #include <bits/stdc++.h>
 2 using namespace std;
 3 #define fr first
 4 #define sc second
 5 #define cl clear
 6 #define BUG puts("here!!!")
 7 #define W(a) while(a--)
 8 #define pb(a) push_back(a)
 9 #define Rint(a) scanf("%d", &a)
10 #define Rll(a) scanf("%I64d", &a)
11 #define Rs(a) scanf("%s", a)
12 #define Cin(a) cin >> a
13 #define FRead() freopen("in", "r", stdin)
14 #define FWrite() freopen("out", "w", stdout)
15 #define Rep(i, len) for(int i = 0; i < (len); i++)
16 #define For(i, a, len) for(int i = (a); i < (len); i++)
17 #define Cls(a) memset((a), 0, sizeof(a))
18 #define Clr(a, x) memset((a), (x), sizeof(a))
19 #define Full(a) memset((a), 0x7f7f7f, sizeof(a))
20 #define lrt rt << 1
21 #define rrt rt << 1 | 1
22 #define pi 3.14159265359
23 #define RT return
24 #define lowbit(x) x & (-x)
25 #define onecnt(x) __builtin_popcount(x)
26 typedef long long LL;
27 typedef long double LD;
28 typedef unsigned long long ULL;
29 typedef pair<int, int> pii;
30 typedef pair<string, int> psi;
31 typedef pair<LL, LL> pll;
32 typedef map<string, int> msi;
33 typedef vector<int> vi;
34 typedef vector<LL> vl;
35 typedef vector<vl> vvl;
36 typedef vector<bool> vb;
37 
38 const int maxn = 33;
39 int dp[maxn][maxn][2];
40 int digit[maxn];
41 int x, y, k, b;
42 
43 int mul(int x, int n) {
44   int ret = 1;
45   while(n) {
46     if(n & 1) ret *= x;
47     n >>= 1; x *= x;
48   }
49   return ret;
50 }
51 
52 int dfs(int l, int cnt, bool fz, bool flag) {
53   if(l == 0) return cnt == k;
54   if(!flag && ~dp[l][cnt][fz]) return dp[l][cnt][fz];
55   int ret = 0;
56   int pos = flag ? digit[l] : b-1;
57   Rep(i, min(pos+1, 2)) {
58     if(i==0 && fz) ret += dfs(l-1, cnt, true, flag&&(i==pos));
59     else ret += dfs(l-1, cnt+i, fz&&(i==0), flag&&(i==pos));
60   }
61   if(!flag) dp[l][cnt][fz] = ret;
62   return ret;
63 }
64 
65 int f(int t) {
66   int pos = 0;
67   while(t) {
68     digit[++pos] = t % b;
69     t /= b;
70   }
71   return dfs(pos, 0, true, true);
72 }
73 
74 signed main() {
75   //FRead();
76   Clr(dp, -1);
77   while(~scanf("%d%d%d%d",&x,&y,&k,&b)) {
78     printf("%d
", f(y) - f(x-1));
79   }
80   RT 0;
81 }
原文地址:https://www.cnblogs.com/kirai/p/5897938.html