cdoj第13th校赛初赛A

http://acm.uestc.edu.cn/#/contest/show/54

A - AC Milan VS Juventus

Time Limit: 3000/1000MS (Java/Others)     Memory Limit: 65535/65535KB (Java/Others)
 

Kennethsnow and Hlwt both love football.

One day, Kennethsnow wants to review the match in 2003 between AC Milan and Juventus for the Championship Cup. But before the penalty shootout. he fell asleep.

The next day, he asked Hlwt for the result. Hlwt said that it scored a:b in the penalty shootout.

Kennethsnow had some doubt about what Hlwt said because Hlwt is a fan of Juventus but Kennethsnow loves AC Milan.

So he wanted to know whether the result can be a legal result of a penalty shootout. If it can be, output Yes, otherwise output No.

The rule of penalty shootout is as follows:

  • There will be 5 turns, in each turn, 2 teams each should take a penalty shoot. If goal, the team get 1 point. After each shoot, if the winner can be confirmed(i.e: no matter what happened after this shoot, the winner will not change), the match end immediately.

  • If after 5 turns the 2 teams score the same point. A new turn will be added, until that one team get a point and the other not in a turn.

Before the penalty shootout begins, the chief referee will decide which team will take the shoot first, and afterwards, two teams will take shoot one after the other. Since Kennethsnow fell asleep last night, he had no idea whether AC Milan or Juventus took the first shoot.

Input

The only line contains 2 integers ab. Means the result that Hlwt said.

0a,b10

Output

Output a string Yes or No, means whether the result is legal.

Sample input and output

Sample InputSample Output
3 2
Yes
2 5
No

Hint

The Sample 1 is the actual result of the match in 2003.

The Sample 2, when it is 2:4 after 4 turns, AC Milan can score at most 1 point in the next turn. So Juventus has win when it is 2:4. So the result cannot be 2:5.

This story happened in a parallel universe. In this world where we live, kennethsnow is a fan of Real Madrid.

思路:最简单也最不容易出错的情况就是把特殊情况都枚举出来。

官方题解:

代码:

 1 #include <fstream>
 2 #include <iostream>
 3 #include <algorithm>
 4 #include <cstdio>
 5 #include <cstring>
 6 #include <cmath>
 7 #include <cstdlib>
 8 #include <vector>
 9 
10 using namespace std;
11 
12 #define PI acos(-1.0)
13 #define EPS 1e-10
14 #define lll __int64
15 #define ll long long
16 #define INF 0x7fffffff
17 
18 
19 
20 int main(){
21     //freopen("D:\input.in","r",stdin);
22     //freopen("D:\output.out","w",stdout);
23     int a,b;
24     scanf("%d %d",&a,&b);
25     if(a>b){
26         int t=a;
27         a=b;
28         b=t;
29     }
30     if(a==b)    {puts("No");return 0;}
31     if(b<=5){
32         if(a==0&&b==4) {puts("No");return 0;}
33         if(a==0&&b==5) {puts("No");return 0;}
34         if(a==1&&b==5) {puts("No");return 0;}
35         if(a==2&&b==5) {puts("No");return 0;}
36         else    {puts("Yes");return 0;}
37     }else{
38         if(b-a>1)   {puts("No");return 0;}
39         else    {puts("Yes");return 0;}
40     }
41     return 0;
42 }
View Code
原文地址:https://www.cnblogs.com/jiu0821/p/4378847.html