解析request的反馈信息

Map<String,String> params = new HashMap<String,String>();
        Map requestParams = request.getParameterMap();
        for (Iterator iter = requestParams.keySet().iterator(); iter.hasNext();) {
            String name = (String) iter.next();
            String[] values = (String[]) requestParams.get(name);
            String valueStr = "";
            for (int i = 0; i < values.length; i++) {
                valueStr = (i == values.length - 1) ? valueStr + values[i]
                        : valueStr + values[i] + ",";
            }
            params.put(name, valueStr);
        }
原文地址:https://www.cnblogs.com/itliucheng/p/5026270.html