fastapi实现页面文件下载功能

from starlette.responses import FileResponse


@app.get("/download/{file_name}")
def main(file_name: str):
    print(file_name)
    basedir = os.path.abspath(os.path.dirname(__file__))
    path = basedir + '\' + str(datetime.datetime.now().date())
    file_path = path + '\' + file_name + '.xlsx'
    print(file_path)
    return FileResponse(file_path)