[LeetCode] Sum of Left Leaves

Find the sum of all left leaves in a given binary tree.

Example:

    3
   / 
  9  20
    /  
   15   7

There are two left leaves in the binary tree, with values 9 and 15 respectively. Return 24.

 题目要求树的所有左叶节点的和,根据题意判断出所有左叶节点,使用递归即可。

class Solution {
public:
    int sumOfLeftLeaves(TreeNode* root) {
        if (root == nullptr)
            return 0;
        if (root->left != nullptr && root->left->left == nullptr && root->left->right == nullptr)
            return root->left->val + sumOfLeftLeaves(root->right);
        return sumOfLeftLeaves(root->left) + sumOfLeftLeaves(root->right);
    }
};
// 6 ms
原文地址:https://www.cnblogs.com/immjc/p/7185703.html