1193-Unknown system variable ‘done’

1、错误描述



 2、错误原因

BEGIN
  DECLARE l_id INT;
  DECLARE l_name VARCHAR(20);
  DECLARE l_age INT;
  DECLARE cur_stu CURSOR FOR SELECT t.id,t.name,t.age FROM t_stu_info t;
  DECLARE CONTINUE HANDLER FOR NOT FOUND SET done=1;

  OPEN cur_stu;
  my_loop:LOOP
     FETCH cur_stu INTO l_id,l_name,l_age;
  IF done=1 THEN
     LEAVE my_loop;
  END IF;
  END LOOP my_loop;
  CLOSE cur_stu;

END
    存储过程中使用的变量done未声明,却使用了


3、解决办法

     先对done变量进行声明,后使用

BEGIN
	DECLARE l_id INT;
  DECLARE l_name VARCHAR(20);
  DECLARE l_age INT;
  DECLARE done INT DEFAULT 0;
  DECLARE cur_stu CURSOR FOR SELECT t.id,t.name,t.age FROM t_stu_info t;
  DECLARE CONTINUE HANDLER FOR NOT FOUND SET done=1;

  OPEN cur_stu;
  my_loop:LOOP
     FETCH cur_stu INTO l_id,l_name,l_age;
  IF done=1 THEN
     LEAVE my_loop;
  END IF;
  END LOOP my_loop;
  CLOSE cur_stu;

END


 


原文地址:https://www.cnblogs.com/hzcya1995/p/13314259.html