LeetCode超过经理收入的员工SQL

Employee 表包含所有员工，他们的经理也属于员工。每个员工都有一个 Id，此外还有一列对应员工的经理的 Id。

+----+-------+--------+-----------+
| Id | Name | Salary | ManagerId |
+----+-------+--------+-----------+
| 1 | Joe | 70000 | 3 |
| 2 | Henry | 80000 | 4 |
| 3 | Sam | 60000 | NULL |
| 4 | Max | 90000 | NULL |
+----+-------+--------+-----------+

给定 Employee 表，编写一个 SQL 查询，该查询可以获取收入超过他们经理的员工的姓名。在上面的表格中，Joe 是唯一一个收入超过他的经理的员工。

+----------+
| Employee |
+----------+
| Joe |
+----------+

解法一：

# Write your MySQL query statement below
select Name as Employee from Employee as a where Salary > (select Salary from Employee where Id = a.ManagerId)

解法二：将两个表做连接，比解法一效率高

# Write your MySQL query statement below
select a.Name as Employee from Employee as a join Employee as b on a.ManagerId = b.Id and a.Salary > b.Salary