1.问题,在开发时每跳转一个页面时会验证是否登录状态,如果没有登录就会跳转到登录页面,在登录后常常需要再跳回刚刚的页面
2.代码流程展示
2.1登录ajax代码展示:
function sloginSubmit() { var mobile = $('#smobile').val(); var password = $('#spassword').val(); if(mobile.length==0){ errorTips("手机号有误",2000); return; } if( password.length==0){ errorTips("请输入验证码",2000); return; } $.ajax({ type : 'POST', url : 'sloginSubmit.html', data: {"mobile":mobile,"password":password}, success : function(data) { if(data.code==0){ if(data.message.length>0){ location.href="${request.contextPath}"+data.message; //这里在登录的时候如果返回的有路径则执行路径的页面跳转 }else{ location.href="${request.contextPath}/wx/index.html"; } }else{ errorTips(data.message,2000); } }, error : function(data) { errorTips(data.message,2000); } }); }
2.2.登录部分代码
jsonMessageView = new JSONMessageView(BusinessConstant.OK,"",null); if(request.getSession().getAttribute("requestPath")!=null){ String path = (String) request.getSession().getAttribute("requestPath"); jsonMessageView = new JSONMessageView(BusinessConstant.OK,path,null); } return jsonMessageView;
2.3中间页面跳转时检测是否登录,以及重新登录后跳转到原来页面
//跳转到常用联系人页面 @RequestMapping("touristMange.html") private ModelAndView contactPersonManage(HttpServletRequest request) { ModelAndView mav=new ModelAndView("/wx/html/touristMange.html"); Member member = super.getMember(); if(member==null) { request.getSession().setAttribute("requestPath","/wx/contacts/touristMange.html");//和跳转时请求的路径一样 mav = new ModelAndView("redirect:/wx/login.html");//用户登录超时时跳转到登录页面 return mav; } return mav; }