[leetcode] 1. Two Sum

原题:

Given an array of integers, return indices of the two numbers such that they add up to a specific target.

You may assume that each input would have exactly one solution, and you may not use the same element twice.

Example:

Given nums = [2, 7, 11, 15], target = 9,

Because nums[0] + nums[1] = 2 + 7 = 9,
return [0, 1].

思路:

暂无

c++代码实现:

class Solution {
public:
    vector<int> twoSum(vector<int>& nums, int target) {
        vector<int> a;
        for(int i=0; i<nums.size()-1;i++)
        {
            for(int j=i+1;j<nums.size();j++)
            {
                if(nums[i]+nums[j]==target)
                {
                    a.push_back(i);
                    a.push_back(j);
                }
            }
        }
        return a;
    }
};

  

原文地址:https://www.cnblogs.com/guweixin/p/10414035.html