Happy Number

题目:

Write an algorithm to determine if a number is "happy".

A happy number is a number defined by the following process: Starting with any positive integer, replace the number by the sum of the squares of its digits, and repeat the process until the number equals 1 (where it will stay), or it loops endlessly in a cycle which does not include 1. Those numbers for which this process ends in 1 are happy numbers.

Example: 19 is a happy number

  • 1^2 + 9^2 = 82
  • 8^2 + 2^2 = 68
  • 6^2 + 8^2 = 100
  • 1^2 + 0^2 + 02 = 1

思路: 我没啥思路。。直接上代码。但是在discussion里有些巧妙地解法。待洒家去看看。

 1     public boolean isHappy(int n) {
 2         HashSet<Integer> set = new HashSet<Integer>();
 3         while (!set.contains(n)) {
 4             set.add(n);
 5             int sum = 0;
 6             while (n != 0) {
 7                 sum += (n % 10) * (n % 10);
 8                 n /= 10;
 9             }
10             if (sum == 1) {
11                 return true;
12             }else{
13                 n = sum;
14             }
15         }
16         return false;
17     }
原文地址:https://www.cnblogs.com/gonuts/p/4470280.html