[CF] 180 E. Cubes

对同类元素双指针扫描

#include<iostream>
#include<cstring>
#include<cstdio>
#include<vector>

#define int long long
using namespace std;

inline int rd(){
  int ret=0,f=1;char c;
  while(c=getchar(),!isdigit(c))f=c=='-'?-1:1;
  while(isdigit(c))ret=ret*10+c-'0',c=getchar();
  return ret*f;
}

int n,m,k;
vector<int> vec[200005];
int ans=0;

signed main(){
  n=rd();m=rd();k=rd();
  for(int i=1;i<=n;i++)vec[rd()].push_back(i);
  for(int i=1;i<=m;i++){
    int cur=0,r=0,siz=vec[i].size();
    for(int l=0;l<siz;l++){
      while(r<siz-1&&cur+vec[i][r+1]-vec[i][r]-1<=k){
        r++;cur+=(vec[i][r]-vec[i][r-1]-1);
      }
      ans=max(ans,r-l+1);
      cur-=vec[i][l+1]-vec[i][l]-1;
    }
  }
  cout<<ans;
  return 0;
}

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原文地址:https://www.cnblogs.com/ghostcai/p/9789629.html