按小时计算两个时间的差值,结果精确到分钟

SELECT  ROUND(( DATEDIFF(minute, '2014/1/3 18:40:00', '2014/1/4 20:00:00') )
              / CONVERT(FLOAT, 60), 1) AS DiffDate

原文地址:https://www.cnblogs.com/fumj/p/4040275.html