Guess Number Higher or Lower -- LeetCode

We are playing the Guess Game. The game is as follows:

 

I pick a number from 1 to n. You have to guess which number I picked.

Every time you guess wrong, I'll tell you whether the number is higher or lower.

You call a pre-defined API guess(int num) which returns 3 possible results (-11, or 0):

-1 : My number is lower
 1 : My number is higher
 0 : Congrats! You got it!

Example:

n = 10, I pick 6.

Return 6.

 思路:二分搜索

// Forward declaration of guess API.
// @param num, your guess
// @return -1 if my number is lower, 1 if my number is higher, otherwise return 0
int guess(int num);

class Solution {
public:
    int guessNumber(int n) {
        int left = 1, right = n;
        while (left <= right) {
            int mid = left + (right - left) / 2;
            //if the num < mid
            if (guess(mid) < 0)
                right = mid - 1;
            //else if the num > mid
            else if (guess(mid) > 0)
                left = mid + 1;
            else return mid;
        }
        return -1;
    }
};

 

原文地址:https://www.cnblogs.com/fenshen371/p/5767362.html