机器人的活动范围

        地上有一个m行和n列的方格。一个机器人从坐标0,0的格子开始移动,每一次只能向左,右,上,下四个方向移动一格,但是不能进入行坐标和列坐标的数位之和大于k的格子。 例如,当k为18时,机器人能够进入方格(35,37),因为3+5+3+7 = 18。但是,它不能进入方格(35,38),因为3+5+3+8 = 19。请问该机器人能够达到多少个格子?

回溯:

private int[][] next = {{0, -1}, {0, 1}, {-1, 0}, {1, 0}};
private int count = 0;
private int rows;
private int cols;
private int threshold;
private int[][] digitSum;
public int movingCount(int threshold, int rows, int cols){
    this.rows = rows;
    this.cols = cols;
    this.threshold = threshold;
    boolean[][] marked = new boolean[rows][cols];
    initDigitSum();
    dfs(marked, 0, 0);
    return count;
}
private void dfs(boolean[][] marked, int r, int c){
    if (r < 0 || r >= rows || c < 0 || c >= cols || marked[r][c]){
        return;
    }
    marked[r][c] = true;
    if (this.digitSum[r][c] > threshold){
        return;
    }
    count++;
    for (int[] n : digitSum){
        dfs(marked, r + n[0], c + n[1]);
    }
}
private void initDigitSum(){
    int[] digitSumOne = new int[Math.max(rows, cols)];
    for (int i = 0; i < digitSumOne.length; i++){
        int n = i;
        while (n > 0){
            digitSumOne[i] += n % 10;
            n /= 10;
        }
    }
    this.digitSum = new int[rows][cols];
    for (int i = 0; i < rows; i++){
        for (int j = 0; j < cols; j++){
            this.digitSum[i][j] = digitSumOne[i] + digitSumOne[j];
        }
    }
}
原文地址:https://www.cnblogs.com/earthhouge/p/11437219.html