二叉树权值最大的叶子节点到权值最小的叶子节点的距离

有一棵二叉树,树上每个点标有权值,权值各不相同,请设计一个算法算出权值最大的叶节点到权值最小的叶节点的距离。二叉树每条边的距离为1,一个节点经过多少条边到达另一个节点为这两个节点之间的距离。 给定二叉树的根节点root,请返回所求距离。

真是醉了,看漏了叶子节点。

代码:

 1 import java.util.*;
 2  
 3 /*
 4 public class TreeNode {
 5     int val = 0;
 6     TreeNode left = null;
 7     TreeNode right = null;
 8     public TreeNode(int val) {
 9         this.val = val;
10     }
11 }*/
12 public class Tree {
13      
14     private TreeNode maxNode;
15     private TreeNode minNode;
16      
17     private boolean stop = false;
18     private int result;
19      
20     public int getDis(TreeNode root) {
21         if(root == null) {
22             return 0;
23         }
24          
25         maxNode = root;
26         minNode = root;
27          
28         getMaxAndMin(root);
29         getMaxLength(root);
30         return result;
31     }
32      
33     private int[] getMaxLength(TreeNode root) {
34          
35         if(root == null)
36             return new int[] {-1, -1};
37         if(root == maxNode)
38             return new int[] {0, -1};
39         if(root == minNode)
40             return new int[] {-1, 0};
41          
42         int[] left = getMaxLength(root.left);
43         int[] right = getMaxLength(root.right);
44          
45         int[] curResult = new int[]{Math.max(left[0], right[0]), Math.max(left[1], right[1])};
46          
47         if(curResult[0] != -1)
48             curResult[0]++;
49         if(curResult[1] != -1)
50             curResult[1]++;
51          
52         if(!stop && curResult[0] != -1 && curResult[1] != -1) {
53             result = curResult[0] + curResult[1];
54             stop = true;
55         }
56          
57         return curResult;
58     }
59      
60     private void getMaxAndMin(TreeNode root) {
61         
62         if(root == null)
63             return;
64         if(root.left == null && root.right == null) {
65             if(root.val < minNode.val) {
66                 minNode = root;    
67             } 
68             if(root.val > maxNode.val) {
69                 maxNode = root;    
70             }
71         }
72         getMaxAndMin(root.left);
73         getMaxAndMin(root.right);
74         
75     }
76 }
原文地址:https://www.cnblogs.com/dsj2016/p/5791300.html