Can you solve this equation?
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 13404 Accepted Submission(s): 5979
Problem Description
Now,given the equation 8*x^4 + 7*x^3 + 2*x^2 + 3*x + 6 == Y,can you find its solution between 0 and 100;
Now please try your lucky.
Input
The first line of the input contains an integer T(1<=T<=100) which means the number of test cases. Then T lines follow, each line has a real number Y (fabs(Y) <= 1e10);
Output
For each test case, you should just output one real number(accurate up to 4 decimal places),which is the solution of the equation,or “No solution!”,if there is no solution for the equation between 0 and 100.
Sample Input
2
100
-4
Sample Output
1.6152
No solution!
Author
Redow
Recommend
lcy | We have carefully selected several similar problems for you: 2289 2298 3400 1551 2446
#include <iostream> #include <cstdio> #include <cstring> #include <cmath> #include <cstdlib> #include <queue> #include <algorithm> using namespace std; double g(double x) { return 8*pow(x,4.0) + 7*pow(x,3.0) + 2*pow(x,2.0) + 3*x + 6; } int main() { int n; double x,y; scanf("%d",&n); while(n--) { scanf("%lf",&y); double left=0; double right=100; double mid; if(y>=g(0)&&y<=g(100)) { while(right-left>1e-10) { mid=(left+right)/2; if(g(mid)<=y) left=mid; else right=mid; } printf("%.4lf ",left); } else printf("No solution! "); } }