选择最优仓库多条件排序算法

java 8之前写法
Collections.sort(cashList, new Comparator<CompareHousePo>() { @Override public int compare(CompareHousePo o1, CompareHousePo o2) { int ca = 0; //按照境内预估费用排序 int a = o1.getCashDeerFee().intValue() - o2.getCashDeerFee().intValue(); if (a != 0) { ca = (a > 0) ? 3 : -1; }else { //按照10天到运送到仓库包裹数量 a = o1.getBaggageNum1() - o2.getBaggageNum1(); if (a != 0) { ca = (a > 0) ? 2 : -2; }else { //按照30天到运送到仓库包裹数量 a = o1.getBaggageNum2() - o2.getBaggageNum2(); if (a != 0) { ca = (a > 0) ? 1 : -3; } } } return ca; } });

java 8 写法
Collections.sort(cashList, (o1, o2) -> {
int ca = 0;
//按照境内预估费用排序
int a = o1.getCashDeerFee().intValue() - o2.getCashDeerFee().intValue();
if (a != 0) {
ca = (a > 0) ? 3 : -1;
} else {
//按照10天到运送到仓库包裹数量
a = o1.getBaggageNum1() - o2.getBaggageNum1();
if (a != 0) {
ca = (a > 0) ? 2 : -2;
} else {
//按照30天到运送到仓库包裹数量
a = o1.getBaggageNum2() - o2.getBaggageNum2();
if (a != 0) {
ca = (a > 0) ? 1 : -3;
}
}
}
return ca;
});

  

原文地址:https://www.cnblogs.com/dreammyone/p/9214418.html