和为s的正数序列-python

思路：参考https://blog.csdn.net/qq_41822235/article/details/82109081 里面的方法4
同时因为python2.7的原因，除法会省去小数点后面的数字，if语句那里加了一句ij == 2tsum，

# -*- coding:utf-8 -*-
class Solution:
    def FindContinuousSequence(self, tsum):
        # write code here
        res = []
        for i in range((tsum)//2+1, 1, -1):
            j = 2*tsum / i
            if i*j == 2*tsum and (j-i+1)>0 and (j-i+1) % 2 == 0:
                res.append([ii+(j-i+1)/2 for ii in range(i)])
        return res