canvas绘制一定数目的圆(均分)

绘制多圆

2016年5月24日12:12:26

绘制一定数目(num)颜色随机的小圆,围成一个大圆。根据num完全自动生成,且小圆自动均分大圆路径(num≥20)。

效果:

images/fe002.jpg

前置技能:(1).Canvas(2).勾股定理、余弦定理、斜率方程、象限、角度与弧度转换等数学知识

HTML:

 

<canvas id="canvas" width="900" height="680">您的浏览器太老,请使用新版谷歌或火狐浏览器访问!</canvas>
<script src="canvas_circle.js"></script>

JS:

 

 

/**
 * Created by suwt on 2016/4/26.
 * 注释部分为一条动态射线
 */
window.onload = function () {
    var canvas = document.getElementById('canvas');
    var context = canvas.getContext('2d');
    loadTeams(context);
};
var circle_x = 350, // 圆心坐标
    circle_y = 350,
    circle_r = 200, // 半径
    team_num = 30, // 小圆数目
    colors = ["#33B5E5","#0099CC","#AA66CC","#9933CC","#99CC00","#669900","#FFBB33","#FF8800","#FF4444","#CC0000"];  //随机颜色组
//加载布局模拟图
function loadTeams(cxt) {
    cxt.beginPath();
    cxt.strokeStyle = 'green';
    cxt.arc(circle_x, circle_y, circle_r, 0, 2 * Math.PI);
    cxt.stroke();
    cxt.closePath();
    seating(cxt)
    setInterval("seating(canvas.getContext('2d'))",1000);
}
//分配小圆座次
function seating(cxt) {
    var angle = 360 / team_num; //角度
    var team_x = 0, team_y = 0;
    var team_r = team_num < 20 ? 30 : Math.sqrt(circle_r * circle_r * 2 * (1 - Math.cos(changeRadian(angle)))) / 2;  
//余弦定理  计算小圆的最大半径     BC²=AB²+AC²-2×AB×AC×cosα  如果小圆数目小于20个,半径最大30(上限)
    for (var i = 0; i < team_num; i < i++) {
        team_x = circle_x + Math.sin(changeRadian(i * angle)) * circle_r;  //角度转弧度
        team_y = circle_y - Math.cos(changeRadian(i * angle)) * circle_r;
        cxt.beginPath();
        //cxt.strokeStyle = 'red';
        cxt.arc(team_x, team_y, team_r, 0, 2 * Math.PI);
        cxt.stroke();
        //cxt.fillStyle = "rgb(0,102,153)";
        cxt.fillStyle = colors[ Math.floor( Math.random()*colors.length ) ];
        cxt.fill();
        //cxt.closePath();
    }
    //x=358;
    //y=358;
    //drawLine(cxt,x,y);
    //setInterval(function(){
    //   x=x+1;
    //    y=y+1;
    //    drawLine(cxt,x,y);
    //},5);
    }
//function drawLine(cxt,x,y) {
//    console.log(x+"---"+y);
//    //cxt.clearRect(0,0,1000,1000);
//    cxt.beginPath();
//    cxt.strokeStyle = "black";
//    cxt.lineWidth = 2;
//    cxt.moveTo(x, y);
//    cxt.lineTo(x+1,y+1);
//    cxt.stroke();
//    cxt.closePath();
//    //cxt.rotate((Math.PI/180)*15);
//}

//角度转换为弧度
function changeRadian(angle) {
    return Math.PI / 180 * angle;
}
 





原文地址:https://www.cnblogs.com/dmcl/p/5856203.html