ES6记录

1、合并两个数组
    let a1 = [1,2,3];
    let b1 = [2,3,4];
    b1 = [...b1,...a1]//[2,3,4,1,2,3]
2、接收数据
    let obj = {
        name:"dengjie",
        nameList:[{
          name:"汤姆"
        }],
      }
  //前面的字段必须跟返回的obj的字段名一直 let {name:person,nameList:[{name:personName}]} = obj; console.log(person,personName)//dengjie 汤姆

  

原文地址:https://www.cnblogs.com/deng-jie/p/11636705.html