[HDOJ3442]Three Kingdoms

广搜(BFS)~ 水题

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1 #include <cstdio>
2 #include <cstring>
3 #include <cstdlib>
4
5 usingnamespace std;
6
7 constint SIZE =64;
8 constint range[] = {2,3,0,2,1};
9 constint dx[] = {-1,0,1,0};
10 constint dy[] = {0,1,0,-1};
11
12 int hi;
13 int wi;
14 int sx;
15 int sy;
16 int ex;
17 int ey;
18 int damage[SIZE][SIZE];
19 char g[SIZE][SIZE];
20
21 struct Q
22 {
23 int x,y,state,hp,pre;
24 }queue[SIZE * SIZE *32];
25
26 bool vis[SIZE][SIZE][32];
27
28 bool legal(int x,int y)
29 {
30 return x >=0&& x < hi && y >=0&& y < wi;
31 }
32
33 int cutDown(int val)
34 {
35 int ret =0;
36 for (int i =0;i <5;i++)
37 if ((val >> i) &1) ret += i +1;
38 return ret;
39 }
40
41 bool bfs(int hp)
42 {
43 int qh =-1;
44 int qe =0;
45
46 int px;
47 int py;
48 int ps;
49 int ph;
50 int nx;
51 int ny;
52 int ns;
53 int nh;
54
55 memset(vis,false,sizeof(vis));
56 queue[0].x = sx;
57 queue[0].y = sy;
58 queue[0].state =0;
59 queue[0].hp = hp;
60 queue[0].pre =-1;
61
62 vis[sx][sy][0] =true;
63
64 while (qh != qe)
65 {
66 qh++;
67
68 px = queue[qh].x;
69 py = queue[qh].y;
70 ps = queue[qh].state;
71 ph = queue[qh].hp;
72
73 if (px == ex && py == ey) returntrue;
74
75 for (int i =0;i <4;i++)
76 {
77 nx = px + dx[i];
78 ny = py + dy[i];
79
80 if (!legal(nx,ny)) continue;
81
82 if (g[nx][ny] !='.') continue;
83
84 nh = ph - cutDown((((~ps) &31) & damage[nx][ny]) &31);
85 ns = ((ps | damage[nx][ny]) &31);
86
87 if (nh <0) continue;
88
89 if (vis[nx][ny][ns]) continue;
90
91 qe++;
92 queue[qe].x = nx;
93 queue[qe].y = ny;
94 queue[qe].state = ns;
95 queue[qe].hp = nh;
96 queue[qe].pre = qh;
97 vis[nx][ny][ns] =true;
98
99 }
100 }
101 returnfalse;
102 }
103 int main()
104 {
105 int cas;
106 scanf("%d",&cas);
107 for (int cc =1;cc <= cas;cc++)
108 {
109 memset(damage,0,sizeof(damage));
110 scanf("%d %d",&hi,&wi);
111 for (int i =0;i < hi;i++) scanf("%s",g[i]);
112 for (int i =0;i < hi;i++)
113 for (int j =0;j < wi;j++)
114 if (g[i][j] =='$') sx = i, sy = j, g[i][j] ='.';
115 elseif (g[i][j] =='!') ex = i, ey = j, g[i][j] ='.';
116 elseif (g[i][j] >='A'&& g[i][j] <='E')
117 {
118 int index = g[i][j] -'A';
119 for (int idx =-range[index];idx <= range[index];idx++)
120 for (int idy =-range[index];idy <= range[index];idy++)
121 if (abs(idx) + abs(idy) <= range[index])
122 {
123 int nx = i + idx;
124 int ny = j + idy;
125 if (legal(nx,ny)) damage[nx][ny] |= (1<< index);
126 }
127 if(g[i][j] =='C') g[i][j] ='.';
128 }
129
130 int ans =-1;
131 for (int i =0;i <16;i++)
132 if (bfs(i))
133 {
134 ans = i;
135 break;
136 }
137 printf("Case %d: %d\n",cc,ans);
138 }
139 return0;
140 }
原文地址:https://www.cnblogs.com/debugcool/p/HDOJ3442.html