BC #50 1001 Distribution money

Distribution money

 
 Accepts: 713
 
 Submissions: 1881
 Time Limit: 2000/1000 MS (Java/Others)
 
 Memory Limit: 65536/65536 K (Java/Others)
Problem Description

AFA want to distribution her money to somebody.She divide her money into n same parts.One who want to get the money can get more than one part.But if one man's money is more than the sum of all others'.He shoule be punished.Each one who get a part of money would write down his ID on that part.

Input

There are multiply cases. For each case,there is a single integer n(1<=n<=1000) in first line. In second line,there are n integer a1,a2...an(0<=ai<10000)ai is the the ith man's ID.

Output

Output ID of the man who should be punished. If nobody should be punished,output -1.

Sample Input
3
1 1 2
4
2 1 4 3
Sample Output
1
-1
 1 #include <stdio.h>
 2 #include <string.h>
 3 
 4 int main()
 5 {
 6     int a[10005];
 7     int n,i,j,k,flg;
 8     while(scanf("%d",&n)!=EOF)
 9     {
10         flg=0;
11         memset(a,0,sizeof(a));
12         for(i=1;i<=n;i++)
13         {
14             scanf("%d",&k);
15             a[k]++;
16         }
17         for(i=0;i<10000;i++)
18         {
19             if(a[i]>(n-a[i]))
20             {
21                 flg=1;
22                 j=i;
23                 break;
24             }
25         }
26         if(flg==1)
27             printf("%d
",j);
28         else
29             printf("-1
");
30     }
31     return 0;
32 }
View Code
原文地址:https://www.cnblogs.com/cyd308/p/4771334.html