Chiaki often participates in international competitive programming contests. The time zone becomes a big problem.
Given a time in Beijing time (UTC +8), Chiaki would like to know the time in another time zone ss.
Input
There are multiple test cases. The first line of input contains an integer TT (1≤T≤1061≤T≤106), indicating the number of test cases. For each test case:
The first line contains two integers aa, bb (0≤a≤23,0≤b≤590≤a≤23,0≤b≤59) and a string ss in the format of "UTC+X'', "UTC-X'', "UTC+X.Y'', or "UTC-X.Y'' (0≤X,X.Y≤14,0≤Y≤90≤X,X.Y≤14,0≤Y≤9).
Output
For each test, output the time in the format of hh:mmhh:mm (24-hour clock).
Sample Input
3 11 11 UTC+8 11 12 UTC+9 11 23 UTC+0
Sample Output
11:11 12:12 03:23
题解：就是时区时间的转换，用sscanf(s+4."%lf",&d);将小数还原到数字d;
算出0时区的时间，再转化8时区即可；
#include<bits/stdc++.h>
using namespace std;
typedef long long LL;
const LL inf=0x3f3f3f3f3f3f3f3fLL;
const int INF=0x3f3f3f3f;
int T,a,b;
char s1[10];
int main()
{
scanf("%d",&T);
while(T--)
{
scanf("%d%d",&a,&b);
int sum=a*60+b;
scanf("%s",s1);
double x;
int num= s1[3]=='+'? 1:-1;
sscanf(s1+4,"%lf",&x);
int cx=(int)(10*x);
sum=sum+cx*num*6-8*60;
int h=sum%(24*60);
if(h<0) h+=24*60;
printf("%02d:%02d
",h/60,h%60);
}
return 0;
}