树分治
求逆元请递推，不然会TLE
开桶记录即可
注意常数
# pragma comment(linker,"/STACK:102400000,102400000")
# include <stdio.h>
# include <stdlib.h>
# include <iostream>
# include <algorithm>
# include <string.h>
# include <vector>
# define IL inline
# define RG register
# define Fill(a, b) memset(a, b, sizeof(a))
using namespace std;
typedef long long ll;
IL ll Read(){
RG char c = getchar(); RG ll x = 0, z = 1;
for(; c < '0' || c > '9'; c = getchar()) z = c == '-' ? -1 : 1;
for(; c >= '0' && c <= '9'; c = getchar()) x = (x << 1) + (x << 3) + c - '0';
return x * z;
}
const int MAXN(200010), INF(2147483647), P(1e6 + 3);
int n, cnt, fst[MAXN], to[MAXN], nxt[MAXN], w[MAXN], k, ansx, ansy;
int size[MAXN], rt, sz, mx[MAXN], vis[MAXN], inv[P], d[P], S[MAXN], top, T[P];
IL void Add(RG int u, RG int v){ nxt[cnt] = fst[u]; to[cnt] = v; fst[u] = cnt++; }
IL void Getroot(RG int u, RG int fa){
size[u] = 1; mx[u] = 0;
for(RG int e = fst[u]; e != -1; e = nxt[e]){
if(vis[to[e]] || to[e] == fa) continue;
Getroot(to[e], u);
size[u] += size[to[e]];
mx[u] = max(mx[u], size[to[e]]);
}
mx[u] = max(mx[u], sz - size[u]);
if(mx[u] < mx[rt]) rt = u;
}
IL void Getdeep(RG int u, RG int fa, RG int dis){
d[u] = dis; S[++top] = u;
for(RG int e = fst[u]; e != -1; e = nxt[e]){
if(vis[to[e]] || to[e] == fa) continue;
Getdeep(to[e], u, 1LL * dis * w[to[e]] % P);
}
}
IL void Solve(RG int u){
vis[u] = 1; T[1] = u;
for(RG int e = fst[u]; e != -1; e = nxt[e]){
if(vis[to[e]]) continue;
top = 0; Getdeep(to[e], u, w[to[e]]);
for(RG int i = 1; i <= top; i++){
RG int x = S[i], y = d[x], z = 0;
z = T[1LL * k * inv[1LL * y * w[u] % P] % P];
if(!z) continue;
if(x > z) swap(x, z);
if(x < ansx || (x == ansx && z < ansy)) ansx = x, ansy = z;
}
for(RG int i = 1; i <= top; i++) if(!T[d[S[i]]] || S[i] < T[d[S[i]]]) T[d[S[i]]] = S[i];
}
for(RG int e = fst[u]; e != -1; e = nxt[e]){
if(vis[to[e]]) continue;
top = 0; Getdeep(to[e], u, w[to[e]]);
for(RG int i = 1; i <= top; i++) T[d[S[i]]] = 0;
}
T[1] = 0;
for(RG int e = fst[u]; e != -1; e = nxt[e]){
if(vis[to[e]]) continue;
rt = 0; sz = size[to[e]];
Getroot(to[e], u);
Solve(rt);
}
}
int main(RG int argc, RG char* argv[]){
mx[0] = INF; inv[1] = 1;
for(RG int i = 2; i < P; i++) inv[i] = (1LL * (-(P / i)) * inv[P % i] % P + P) % P;
while(scanf("%d%d", &n, &k) != EOF){
Fill(fst, -1); Fill(vis, 0);
rt = cnt = 0; sz = n; ansx = ansy = n + 1;
for(RG int i = 1; i <= n; i++) w[i] = Read();
for(RG int i = 1, u, v; i < n; i++) u = Read(), v = Read(), Add(u, v), Add(v, u);
Getroot(1, 0); Solve(rt);
if(ansx > n) puts("No solution");
else printf("%d %d
", ansx, ansy);
}
return 0;
}