软件工程个人作业1(修改后)

设计思路:

  1.定义数组 char a[]={‘+’,’-’,’*’,’/’};

   2.利用for循环进行30个算法的输出;

       其中定义j=(int)(Math.random()*4);来随机对应相应的运算符a[j]

        判断当为除法运算时分母是否为零,为零则停止本次运算;

代码:

package 算法;

public class suanfa {

 public static void main(String[] args) {
  // TODO Auto-generated method stub
     char a[]={'+','-','*','/'};
     int i,j;
     double b[]= new double[30];
     double c[]=new double[30];
      double d[]=new double[30];
     for( i=0;i<30;i++)
     {
         b[i]=(int)(Math.random()*99); 
         c[i]=(int)(Math.random()*99);
         j=(int)(Math.random()*4);
         if(c[i]==0&&a[j]=='/') continue;
         if(a[j]=='+')d[i]=b[i]+c[i];
         if(a[j]=='-')d[i]=b[i]-c[i];
         if(a[j]=='*')d[i]=b[i]*c[i];
         if(a[j]=='/')d[i]=b[i]/c[i];
         System.out.println(" "+b[i]+" "+a[j]+" "+c[i]+" =___;"+"   运行结果为:"+d[i] );
     }
 }

}

实验截图:

原文地址:https://www.cnblogs.com/chenpengmeng/p/5251923.html