[算法] 二分查找(C++)

不想废话了!

条件:升序数组;

结果:找得到的话返回 数组下标,找不到则返回 -1

循环

//二分查找-循环(升序数组)
int binarySearch(vector<int>& nums, int target) {
    int start = 0, end = nums.size() - 1, mid = 0;
    while (start <= end) {
        //mid=(start+end)/2;    //可以用这个,但是 "start+end" 有可能会造成溢出
        mid = start + (end - start) / 2;
        if (nums[mid] == target)
            return mid;
        else if (nums[mid] > target)
            end = mid - 1;
        else
            start = mid + 1;
    }
    return -1;
}

递归

int search(vector<int>& nums, int target) {
    return binarySearch(nums, target, 0, nums.size() - 1);
}
//二分查找-递归(升序数组)
int binarySearch(vector<int>& nums, int target, int start, int end) {
    if (start > end)
        return -1;
    int mid = (start + end) / 2;
    if (nums[mid] == target)
        return mid;
    else if (nums[mid] > target)       //大于目标,则需要往前找
        return binarySearch(nums, target, start, mid - 1);
    else                               //小于目标,则需往后找
        return binarySearch(nums, target, mid + 1, end);
}

 三个部分

  • 终止条件;
  • 中间值是否符合;
  • 继续查找;
原文地址:https://www.cnblogs.com/chasemeng/p/15008772.html